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          Solving  Linear - Quadratic Systems 
          
				A quadratic equation is defined as 
				an equation in which one or more of the termsis squared but 
				raised to no higher power.
 
					
						
							| Linear - quadratic system: Line & Parabola (where  only one 
							variable is squared)
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              | Solve graphically: | y = -x2 + 2x + 4  (quadratic - 
				parabola) x + y = 4  (linear)
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              | 1. | Change the linear equation 
				to "y=" form. | y = -x + 4 |  
              | 2. | Enter
                the equations as "y1=" and 
				"y2=". (Be
                sure to use the negative key, not the subtraction key, for 
              entering negative values.)
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              | 3. | Hit GRAPH 
				to see if and where the graphs intersect. (Using  ZOOM
                #6: ZStandard creates a 10 x 10 
              viewing window.
 You may need to adjust the WINDOW to see a clear picture of the intersection locations for the 
			  two graphs.)
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              | 4. | Under CALC (2nd 
				Trace) choose #5 intersect to find the points where the graphs intersect. | 
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              | 5. | When prompted for the "First curve?", move the spider on, 
			  or near, a point of intersection.  Hit  Enter.   | 
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              | 6. | When prompted for the "Second curve?", just hit Enter.     | 
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              | 7. | Ignore the prompt for "Guess?", and hit Enter.       | 
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              | 8. | Read the answers as to the 
				coordinates of the point of intersection.  These 
				coordinates appear at the bottom of the screen.  Point of intersection 
				(left side):  
			  (0,4) | 
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              | 9. | If your graphs have a 
				second point of intersection, repeat this process to find the 
				second point.  Choose the #5 
				intersect choice and repeat the steps for finding the 
				intersection.  Point of intersection (right side):  
			  (3,1) | 
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							| Linear - quadratic system: Line & Circle (where  both 
							variables are squared)
 |  In a linear- quadratic system where BOTH variables in the quadratic are squared, the graphs will be a cirlce and a straight line.  When graphing a circle and a straight 
					    line on the same set of axes, three situations are 
	      possible. 
			  
			    
			      |  |  |  |  
			      | The equations will intersect in two locations.  
			        Two real solutions. | The equations will intersect in one location (a tangent).  One real solution. | The equations will not intersect. No real solutions.
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              | Solve graphically: | x2 + 
				y2 = 25  (quadratic - circle) x - y = 5  (linear)
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              | 1. | Change the linear equation 
				to "y=" form. | y = x - 5 |  
              | 2. | Change the quadratic 
				equation to "y=" form. 
					
						|  | 
							
								
									|  can be entered as two separate entries:
 
  or a "list" notation may be used:
 
  |  |  |  Enter the equations.
 The circle entry shown here uses the "list" notation.
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              | 3. | 
					Choose  ZOOM #5: ZSquare to get a true 
				looking circle.
						| If you hit GRAPH 
						at this point using a standard window (ZOOM 
						#6: ZStandard)  your circle will 
						not resemble a circle due to the 3 to 2 aspect ratio of 
						this screen. | 
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 |  Notice the missing pixels near the x-axis.
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              | 4. | Under CALC (2nd 
				Trace) choose #5 intersect to find the points where the graphs intersect. | 
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              | 5. | We will find the left 
				point of intersection first. 
              When prompted for the "First curve?", use the  down arrow key to move to the 
			  bottom portion of the circle.  Hit  Enter.   | 
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              | 6. | When prompted for the "Second curve?", just hit Enter.     | 
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              | 7. | Ignore the prompt for "Guess?", and hit Enter.       | 
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              | 8. | Read the answers as to the 
				coordinates of the point of intersection.  These 
				coordinates appear at the bottom of the screen.  Point of intersection 
			  (left side):  (0,-5) | 
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              | 9. | We will find the right 
				point of intersection next.  This point is occurring 
				where the missing pixels are located.  We need to  zoom in at this location to 
				place more pixels on the screen. After zooming, go to CALC (2nd 
    Trace), choose #5 intersect, and find the points where the graphs intersect. |  |  
              | 10. |  30b Notice the graph is set to Y1.    
				Use up and down arrows to get Y2.
 |  No need to guess.  Hit ENTER.
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              | 11. | Point of intersection (right 
                side):  (5,0)   Solution: (0,-5) and (5,0) |  |  
              | When working with a circle, always check the 
				equation statement in the upper left corner to see where you 
				are.  The up and down arrows will move you between the 
			  equations. |  |